Question

If one of the polynomial p(x) = ax 3 (a-1) x-1 is 1, then the value of 'a' is ?
a)1
b)-1
c)2
d) - 2​

Answer 1

      :

Correct option is

A

1

Given: p(x)=ax

2

−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1