if one of the quadratic polynomial (k^2+k)x^2+68x+6k is reciprocal of other, find k
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Since one root is reciprocal of other,
product of the roots is 1.
i.e., 6k / (k^2+k) = 1
k^2 - 5k = 0
k(k-5) = 0
k = 0 or 5.
k = 0 is not admissible since it makes coefficient of x^2 = 0.
Therefore k = 5
product of the roots is 1.
i.e., 6k / (k^2+k) = 1
k^2 - 5k = 0
k(k-5) = 0
k = 0 or 5.
k = 0 is not admissible since it makes coefficient of x^2 = 0.
Therefore k = 5
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