if one of the quadratic polynomial x^2+x-2 is -2 find the other zero
Answers
Answered by
2
Answer:
x^2+x-2 = -2
compare it with ax²+bx+c =0
a= 1, b= -p , c= -p-c
α and β are two zeroes
i) sum of the zeros= -b/a
α+β = - (-p)/1= p -----(1)
ii) product of the zeroes = c/a
αβ = (-p-c) /1 = -p-c -----(2)
now take
lhs = (α+1)(β+1)
= α(β+1) +1(β+1)
=αβ +α +β +1
=-p-c+p+1 [from (2) and (1) ]
= -c+1
=1 -c
=RHS
Hope Correct because i am very bad in Maths.
Similar questions