If one of the root of equation is x²-7x+k=0 is 2 find the value of k
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Answer:
k=10
Step-by-step explanation:
it is given that one root is 2
so we put 2 as p(x)
p(x)= x²-7x+k=0 ( x=2)
p(2)=(2)²-7(2)+k=0
4-14+k=0
-10+k=0
k=10
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