Question

if one of the root of equation X square + 7 x + k = 0 is -2 then find the other root​

Answer 1

Answer:

$p(x)=x^{2} +7x+k=0\\ \\ \alpha =-2 ,\beta=? \\ \\ \alpha +\beta =\frac{-b}{a} \\ \\ -2+\beta =\frac{-7}{1} \\ \\ \beta =-7+2\\ \\ \beta =-5$

Other root=-5

Answer 2

$\large{\mathfrak{\underline{\underline{Answer :-}}}}$

Given :

✯ p(x) = x² - 7x + k = 0

⟹ First root (α) = -2

⟹ a = 1

⟹ b = 7

To Find :-

⇒ Other root (β) = ?

Solution :-

Using Formula

$\huge{\boxed{\boxed{\alpha \: + \:</p><p>\beta \: = \: \frac{-b}{a}}}}$

___________[Putting values]

⇒ - 2 + β = -7/1

⇒ β= −7 + 2

⇒ β = −5

$\huge{\boxed{\boxed{Other \: root \:-5}}}$