if one of the root of polynomial x²+3x+6 Is k find its another root
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Answered by
1
Answer:
(-3±15i) /2
Step-by-step explanation:
k= -3±(√(9-(4)(1)(6)))/2
k= -3±(√(9-24))/2
k= (-3±15i)/2
Answered by
1
Step-by-step explanation:
2 is a zero of x²+3x+k.
Thus, (2)² +3(2)+k=0
k+10=0
k=−10
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