If one of the root of quadratic equation is as follows Find the values of 'h' and 'k'.
solve 2)
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h = 2√6
( 2√6 )² - 10(2√6) +2k = 0
4×6 - 20 √6 + 2k
24-20√6 = -2k
4 ( 6 - 5 √6 ) = - 2k
k = -2 ( 6 - 5√ 6 )
( 2√6 )² - 10(2√6) +2k = 0
4×6 - 20 √6 + 2k
24-20√6 = -2k
4 ( 6 - 5 √6 ) = - 2k
k = -2 ( 6 - 5√ 6 )
VivekMunde:
can u explain the very first step
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