Math, asked by navnathdighe421, 2 months ago


If one of the root of quadratic equation x2 - 10x + 2k=0 is (h+2/6) Find the values
of h & k.

Answers

Answered by Anonymous
1

Answer:

Hey Mate!!

I hope this will help you!!

h+2 √6 is an irrational root.

Irrational roots always occur in conjugate pairs.

Therefore, h-2 √6 is also a root of the quadratic. Sum of the roots = - b/a

=> h+2 √6 + h-2 √6 = -(-10/1) = 10

=> 2h = 10 => h = 5.

Product of the roots = c/a

=> (h+2 √6)(h-2 √6) = 2k/1

=> (5+2 √6)(5–2√6) = 2k

=> 25- 24 = 2k => k = 1/2

Therefore, h = 5 and k = 1/2.

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