Question

If one of the root of quadratic equation x²+kx+54=0 is -6 then complete the following activity to find the value of 'k'.​

Answer 1

Answer:

k=3

Step-by-step explanation:

$\sf \: Let's \: take \: \red{x= 6} \\ \sf \: ( - 6) {}^{2} + k( - 6) + 54 = 0\\ \sf \red{ - 36} - 6k + 5 = 0\\ \sf \: - 6k + \red{18} = 0\\ \sf \: k = \red{3}$

$\huge \bold{@ParkStanley}$