if one of the root of the quadratic equation kx^2+2x-8=0is -2 then what is the value of k
Answers
Answered by
11
Answer:
- k = 3
Explanation:
Given polynomial,
⇒ p(x) = kx² + 2x - 8 = 0
Where one the root is -2
We need to find the value of ‘k’
Substituting the value of x in p(x)
⇒ p(-2) = k(-2)² + 2(-2) - 8
⇒ k(4) - 4 - 8 = 0
⇒ 4k - 12 = 0
⇒ 4k = 12
⇒ k = 12/4
⇒ k = 3
Hence, the value of ‘k’ is 3
Answered by
2
Answer:
Hence,The value of k is 3!!!
Hope this helps u mate ✔️
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