Question

if one of the root of the quadratic equation
x²-7x+k=0 is 4 find the value of k​

Answer 1

Answer:

x^2-7x+k=0

4^2-7(4)+k=0

16-28=-k

-12=-k

k=12

Answer 2

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x - 7x + k = 0

a=1 , b= (-7) , c = k

Let the other root be x

therefore

4 + x = sum of zeroes = -b/a =7/1

therefore

x =7-4 =3

therefore

x*4 = 3*4 = product of zeroes = c/a

therefore,

12 =k/1

Therefore k = 12