Question

if one of the root's of quadratic equation
$x2 - 3x - p = 0 is5 \: find \: p$
​

Answer 1

$answer$

${x}^{2} - 3x - p = 0$

Putting x = 5 in given equation,

${5}^{2} - 3(5) - p = 0$

$25 - 15 - p = 0$

$- p = - 10$

$p \: \: = \: \: 10$

Therefore p = 10.

Answer 2

$\huge\underline\mathbb\red{Solution}$

${x}^{2} - 3x - p = 0 \\ Now \: putting \: the \: value \:of \: x =5,\: we \: get \\ {5}^{2} - 3(5) - p = 0 \\ = > 25 - 15 - p = 0 \\ = > 10 - p = 0 \\ = > - p = - 10 \\ p = 10$

$The \: required \: value \: of \: p \: is \: 10$

$\huge\mathfrak\red{Hope \: it \: helps \: uhh}$