If one of the roots of 2x2-5x+k=0 is 7/2, then k=
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Answer:
k = 9/2
Explanation:
compare 2x²-6x+k=0 with
ax²+bx+c=0, we get
a = 2 , b = -6 , c = k
Discreminant (D) = 0
[ Since, roots are real and equal]
b²-4ac = 0
=> (-6)² -4×2×k = 0
=> 36 -8k = 0
=> -8k = -36
=> k = (-36)/(-8)
=> k = 9/2
Therefore,
k = 9/2
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