Question

If one of the roots of quadratic equation X2 – kX + 27 = 0 is 3 then find

the value of ‘k’.​..​

Answer 1

Question:-

If one of the roots of quadratic equation x² - kx + 27 = 0 is 3 then find  the value of ‘k’.

To Find:-

Find the value of k.

Solution:-

Given ,

One of root of the equation is 3.

Let the value of x is 3

$\longrightarrow\sf \: { 3 }^{ 2 } - 3k + 27 = 0$

$\longrightarrow\sf \: 9 - 3k + 27 = 0$

$\longrightarrow\sf \: 36 - 3k = 0$

$\longrightarrow\sf \: 3k = 36$

$\longrightarrow\sf \: k = \cancel\dfrac { 36 } { 3 }$

$\longrightarrow\sf \: k = 12$

Hence ,

The value of k = 12

Answer 2

Answer:

Question:-

If one of the roots of quadratic equation x² - kx + 27 = 0 is 3 then find the value of ‘k’.

To Find:-

Find the value of k.

Solution:-

Given ,

One of root of the equation is 3.

Let the value of x is 3

\longrightarrow\sf \: { 3 }^{ 2 } - 3k + 27 = 0⟶3

2

−3k+27=0

\longrightarrow\sf \: 9 - 3k + 27 = 0⟶9−3k+27=0

\longrightarrow\sf \: 36 - 3k = 0⟶36−3k=0

\longrightarrow\sf \: 3k = 36⟶3k=36

\longrightarrow\sf \: k = \cancel\dfrac { 36 } { 3 }⟶k=

3

36

\longrightarrow\sf \: k = 12⟶k=12

Hence ,

The value of k = 12