Question

If one of the roots of the equation
$a {x}^{2} + bx + c = 0$
be reciprocal of one of the roots of
$a1 {x}^{2} + b1x + c1$
then prove that
$(aa1 - cc1) = (bc1 - ab1)(b1c - a1b)$
​

Answer 1

Step-by-step explanation:

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