if one of the roots of the equation x²-5x+k=0 is equal to 4,find the values of k.
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Heya..!
Given ,
p(x)=x^2-5x+k=0
=4^2-5(4)+k=0
=16-20+k=0
= 16+k=0+20
=16+k=20
k=20-16
k=4
Therefore Value Of K = 4
Hope This Helps You ..!
Given ,
p(x)=x^2-5x+k=0
=4^2-5(4)+k=0
=16-20+k=0
= 16+k=0+20
=16+k=20
k=20-16
k=4
Therefore Value Of K = 4
Hope This Helps You ..!
where is the question ..?
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