Question

If one of the roots of the equation x2 + 6x + k = 0 is 4, the other root is - 10

True or False​

Answer 1

$\textbf{Given:}$

$\textsf{One root of the equation}\;\mathsf{x^2+6x+k=0\;is\;4}$

$\textbf{To check:}$

$\textsf{-10 is other root or not}$

$\textbf{Solution:}$

$\textsf{Let the other root be}\;\beta$

$\mathsf{Then,}$

$\mathsf{Sum\;of\;the\;roots=\dfrac{-b}{a}}$

$\implies\mathsf{4+\beta=\dfrac{-6}{1}}$

$\implies\mathsf{4+\beta=-6}$

$\implies\mathsf{\beta=-6-4}$

$\implies\mathsf{\beta=-10}$

$\therefore\textsf{The other root is -10}$

$\textbf{Find more:}$

If the roots of x^2 -bx/ax-c = k-1/k+1 are numerically equal and opposite in sign then k=?​

https://brainly.in/question/16638285

Answer 2

Answer:

true

Step-by-step explanation:

(4)²+6(4)+k=0

16+24+k=0

k(-40)

(-10)²+6(-10)+(40)

100-60-40=0

0=0

Ans True

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