Question

if one of the roots of the equation x²+bx+c=0, is 3i-4, find value of c​

Answer 1

Answer:

Step-by-step explanation:

Another root is 3i+4

Let the roots of the equation is a&b

Then x²-x(a+b)+ab=x²+bx+c .......(i)

=>a+b=3i+4+3i-4=6i

&ab=(3i+4)(3i-4)=9i²-16=-9-16=-25

Substitute a+b&ab values in (i) we get

x²-x6i-25=x²+bx+c

c=-25

Answer 2

Answer:

value of C is -4

Step-by-step explanation:

suppose it x is 1 and bx is 3 so 3+1=4 and 4+-4 =0