Question

if one of the roots of the quadratic equation is ax^2 +7x-6=0 is 3 then a=?​

Answer 1

       $\underline{\bold{Solution:}}$

       $\text{It is given that, one of the roots of }ax^{2} + 7x - 6 \text{ is }3$

$\implies a(3)^{2} + 7(3) - 6 = 0$

$\implies 9a + 21 - 6 = 0$

$\implies 9a + 15 = 0$

$\implies 9a = -15$

$\implies a = -\dfrac{15}{9}$

$\implies \boxed{a = -\dfrac{5}{3}}$

Answer 2

Answer:

-5/3

Step-by-step explanation:

Substitute x = 3 into the given equation, 9a + 21 - 6 = 0.

Therefore, 9a = -15, implies a = -15/9 = -5/3.

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