If one of the roots of the quadratic equation Kx2
+2x-8=0is -2 then find the value of k
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3
Answer:
3
Step-by-step explanation:
f(x) =kx²+2x-8=0
-2 is the root of f(x)
f(-2) =0
→k(-2)²+2(-2) -8=0
→4k-4-8=0
→4k-12=0
→4k=12
→k=12/4
→k=3
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