If one of the roots of the quadratic equation x^2-11x+k=0. Is 9 then value of k
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b^2-4ac
a=1 b=-11 c=k
(-11)^2-4(1)(k)
121-4k=0
121=4k
k=121/4
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Answer:
Step-by-step explanation:
a, (a-2) are roots,
a+a-2 =k,
2a-2=k
a(a-2)= 3,
a^2β2a-3=0,
(a+1)(a-3)=0,
a=-1, a=3
(1) If a=-1, k=-4
(2) if a=3, k=4
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