Question

If one of the roots of the real quadratic equation is 2-root3 , the equation is :- ​

Answer 1

$x = 2 - \sqrt{3}$

$(x - 2) {}^{2} = ( - \sqrt{3} ) {}^{2}$

$x {}^{2} - 4x + 4 = 3$

$x {}^{2} - 4x + 1 = 0$

Answer 2

Answer:

THE EQUATION IS : x²-4x+1.

Step-by-step explanation:

NOW ,

IF ONE ROOT OF THE EQUATION IS 2-√3 , THEN THE OTHER ROOT WILL BE 2+√3.

NOW THE REQUIRED QUADRATIC FORMULA IS:

⇒    x² - (SUM OF ZEROES) + (PRODUCT OF ZEROES)

⇒    x² - (2-√3+2+√3) + ((2+√3)(2-√3)

⇒    x² - 4x + 1

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