Question

If one of the roots of the two equations x^2 + bx+ 12 = 0 and x ^2 + bx + q = 0 ,then what is the value of q.​

Answer 1

Answer:

q=12

Explanation:

$x^{2} +bx+12=0$  - eq 1

$x^{2} +bx+q = 0$    - eq 2

eq 1 is equal to eq 2 as both of them are equal to the same no. (0=0)

$x^{2} +bx+12=x^{2} +bx+q\\x^{2} -x^{2} +bx-bx+12=q\\12=q$

So the value of q=12

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Answer 2

Answer:

12 is the correct answer.....