Question

if one of the roots of x²+kx+1=0
is square of the other then k= ?​

Answer 1

Step-by-step explanation:

k=-2

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Answer 2

Answer:

 k = - 2

Step-by-step explanation:

Let a be a root of the equation

Then $a$ , $a^2$ become the roots of the equation

$a$ + $a^2$ = $-k$ —(1) and

$a$ * $a^2$ = $1$ —(2)

Since for a Quadratic Equation of the type

$ax^2 +bx +c$

sum of roots = -b/a (here b = k and a = 1)

Product of roots = c/a (here c = 1)

      $a^3=1\\\\=>a=1$

Substituting a in (1) we get,

$1+1^2=-k\\\\=>k=-2$

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