Question

if one of the zero of 2xsq+3x + k is reciprocal of other then find the value of k and the other zero​

Answer 1

The vaue of k is "2".

Step-by-step explanation:

The given quadratic poynomial 2$x^{2}$ + 3x + k.

Here, a = 2, b = 3 and c = k

Let α and $\frac{1}{α}$ be the reciprocal of quadratic poynomial.

We know that,

Product of zeroes = $\frac{c}{a}$

⇒ α·$\frac{1}{α}$ = $\frac{k}{2}$

⇒ 1 = $\frac{k}{2}$

⇒ k = 2

Hence, the vaue of k is "2".