If one of the zero of polynomial Kx^2+10x+K is -1/3 then find the value of K.
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The value of k is 3.
Hope this will help you....
Hope this will help you....
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Hello !
p(x) = kx² + 10x + k
p(-1/3) = 0
p(-1/3)= k × (-1/3)² + 10 × -1/3 + k
k × 1/9 - 10/3 + k = 0
k/9 + k = 10/3
lcm = 9
k/9 + 9k/9 = 10/3
10k/9 = 10/3
10k = 10/3 × 9
10k = 30
k = 30/10
k = 3
p(x) = kx² + 10x + k
p(-1/3) = 0
p(-1/3)= k × (-1/3)² + 10 × -1/3 + k
k × 1/9 - 10/3 + k = 0
k/9 + k = 10/3
lcm = 9
k/9 + 9k/9 = 10/3
10k/9 = 10/3
10k = 10/3 × 9
10k = 30
k = 30/10
k = 3
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