Question

if one of the zero of the polynomial 2x^2+3x+K is 1/2. Find K and hence find the other zeros​

Answer 1

Answer:

-5/2

Step-by-step explanation:

If one zero is 1/2

than x-1/2=0

x=1/2

put this value in equation

2x^2+3x+K

2(1/2)²+3(1/2)+k=0

2/4+3/2+k=0

(2+6)/4+k=0

10/4+k=0

k=-10/4= -5/2

I think it is helpful for you

Answer 2

Answer:

K = -2 & the zeros of the polynomial are: (2x-1)(x+2)

Step-by-step explanation:

p(x) = 2x^2 +3x +K

x = 1/2

=> p(1/2) = 2 × (1/2)^2 +3 × (1/2) + K

=> 2 × 1/4 +3/2 +K = 0

=> 1/2 +3/2 + K = 0

=> 2 + K = 0

=> K = -2

Now the polynomial is:

2x^2 + 3x -2 = 0

splitting the middle ter. we get:

2x^2 +4x -x -2 = 0

=> 2x(x+2) -(x+2)

=> (2x-1)(x+2)