Question

if one of the zero of the polynomial (3x^3-x^2-kx+1) is 1, then k will be

Answer 1

Step-by-step explanation:

${3x}^{3} - {x}^{2} - kx + 1$

putting x=1

$3 ({1}^{3} ) - 2( {1}^{2} ) - k + 1 = 0$

3-2-k+1=0

1+1-k=0

2-k=0

K=-2

Answer 2

Step-by-step explanation:

Given one zero of the polynomial 3x³-x²-kx+1 is 1

Substitute x=1 in the polynomial for which it will be =0

3(1)³-(1)²-k(1)+1=0

3-1-k+1=0

k=3