Question

if one of the zero of the polynomial 3x²-8x+2k+1 is seven times the other ,then find the other zeros and value of k

Answer 1

Heya!!Here is your answer friend ⤵⤵

Please refer to the attachment for the solution ♥

Hope it helps you ✌✌

Answer 2

==================

Zeroes :

$\alpha \: and \: 7 \alpha$
now,

$\alpha + \beta = \frac{ - b}{a}$

$= > \alpha + 7 \alpha = \frac{8}{3} \\ \\ = > 8 \alpha = \frac{8}{3} \\ \\ = > \alpha = \frac{1}{3}$

hence ,zeroes are 1/3 and 7/3

on putting this value intead of x we have:

=>1/3-8/3+2k+1=0

=>-7/3+1+2k=0

=>-4/3+2k=0

=>2k=4/3

=>k=2/3

<<<<<<<<<<❤>>>>>>>>>>>