If one of the zero of the polynomial p(x)=(a^2+9)x^+45x+6a is reciprocal of the other , find the value of a.
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Step-by-step explanation:
Let it's two zeros be x and y
xy = 6a/(a² + 9 )
x = 1/y. Given
x(1/x) = 6a/ ( a² + 9 )
a² + 9 = 6a
a² - 6a + 9 = 0
a² -3a - 3a + 9 = 0
a ( a - 3 ) -3 ( a - 3 ) = 0
a = 3
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