Question

if one of the zero of the polynomial x²+3x+k is 2 then the value of k is​

Answer 1

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

$\huge{\boxed{\rm{\red{Concept \:used}}}}$

A real number is a is said to be a zero

of the polynomial p(x) if p (a)=0

$\huge\bold{\underline{\underline{{Given:-}}}}$

2 is one zero of the polynomial x^2 +3x+ k

$\huge\bold{\underline{\underline{{To\: find\: k:-}}}}$

since 2 is one zero of the polynomial x^2+ 3x +k,we have

➢ 2^2 + 3 (2) + k= 0

➢ 4 + 6+ k = 0

➢ 10 + k = 0

$\implies\boxed{\bf,k= -10}$

The value of k is - 10

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer 2

$\huge\purple{\mathbb{HEYA \: BUDDY}}$

$\large\red{\sf{<u>Question</u>:-}}$

If one of the zero of the polynomial x²+3x+k is 2 then the value of k is?

$\large\red{\sf{<u>Answer</u>:-}}$

Since 2 is one of the zero of the polynomial

${x}^{2} + 3x + k$

Therefore, putting value of x = 2 in the above equation, we get,

$<font color = blue>$

${2}^{2} + 3(2) + k$

=> 4 + 6+ k = 0

=> 10 + k = 0

=> k = -10.

$<font color = black>$

Which is the required answer.

Thanks.