Math, asked by SreeVUK, 1 year ago

If one of the zero of the quadratic equation p(x)= 4x^{2} -8kx+9 is negative of the other, then find the value of k

Answers

Answered by Arshpreet111
1
4x^2-8kx+9=0
D=b^2-4ac
D=64k^2-144
D=0
64k^2=144
k^2=144/64
k=3/2

SreeVUK: Thanks so much!
Answered by Anonymous
0

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :- -------

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.

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