If one of the zero of the quadratic equation p(x)= 4x^{2} -8kx+9 is negative of the other, then find the value of k
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Answered by
1
4x^2-8kx+9=0
D=b^2-4ac
D=64k^2-144
D=0
64k^2=144
k^2=144/64
k=3/2
D=b^2-4ac
D=64k^2-144
D=0
64k^2=144
k^2=144/64
k=3/2
SreeVUK:
Thanks so much!
Answered by
0
Step-by-step explanation:
Answer :-
→ k = 0 .
Step-by-step explanation :- -------
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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