If one of the zero of the quadratic polynomial 2x2+kx-15 is 3 find the other zero and value of k
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Answered by
117
Hii there!!
Plz refer to the attachment for the solution.
Hope it helps. ...
Plz refer to the attachment for the solution.
Hope it helps. ...
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shirleydsouza:
Thank u !
Answered by
50
Answer:
Value of k = -1,
Value of k = -1,Other zero = 5/2
Step-by-step explanation:
Let p(x)=2x²+kx-15,
Given 3 is one zero of p(x).
Then ,
p(3)=0
=> 2(3²)+k(3)-15=0
=> 18+3k-15=0
=> 3k + 3 = 0
=> 3k = -3
Divide each term by 3 ,we get
=> k = -1
Put k = -1 , in p(x) , we get
p(x)= 2x²-x-15
Splitting the middle term, we get
= 2x²-6x+5x-15
= 2x(x-3)+5(x-3)
=(x-3)(2x-5)
Take 2x-5=0
=> x=5/2
Therefore,
Value of k = -1,
Other zero = 5/2
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