Question

if one of the zero of the quadratic polynomial bracket K - 1 bracket close K square + kx + 1 is -3 then the value of k is

Answer 1

okkm

1 zero=(k-1)

k^2+kx+1=-3

wait I'm sending the photo but I'll have to mark brainliest

sry I don't.have time I'll

answer later

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8. ....

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .