If one of the zero of the quadratic polynomial f(x)=4x^2-8hx-9 is equal in magnitude but opposite in sign of the other, find the value of h.
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let a and b be the two zeroes
given a = - b
sum of zeroes = - (- 8h)/4 =8h/4 = 2h = a + b
a + b = 2h
( - b) + b =2h
- b + b =2 h
0 = 2h
h = 0
: the value of h is 0
hope it helps you
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