Question

if one of the zero of the quadratic polynomial (k-1) x2 +kx +1=o is -3 then the value of k is ​

Answer 1

Answer:

k = 4/3

Step-by-step explanation:

(k-1)x² + kx + 1 = 0

x = -3

$(k - 1) {( - 3)}^{2} + k( - 3) + 1 = 0 \\9 (k - 1) - 3k + 1 = 0 \\ 9k - 9 - 3k + 1 = 0 \\ 6k - 8 = 0 \\ 6k = 8 \\ k = \frac{8}{6} \\ k = \frac{4}{3}$

verification

$( \frac{4}{3} - 1) {( - 3)}^{2} + \frac{4}{3} ( - 3) + 1 \\ = ( \frac{4 - 3}{3} )(9) + ( - 4) + 1 \\ = \frac{1}{3} (9) - 4 + 1 \\ = 3 - 4 + 1 \\ = - 1 + 1 \\ = 0$

Hope you get your answer