Question

If one of the zero of4x2-9-8kx is negative of the other find k​

Answer 1

Explanation:

Let one of Zero of the polynomial be " T"

then the other zero will be negative of it that is -T

so,

equate the quadratic equation to zero as it satisfies it.

By question

4x² - 9 - 8kx = 0

sum of zeroes = -b/a

T +(-T) = -(-8k)/4

0 = 2k

2k = 0

K = 0

2nd solution:--

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sriti88 Genius

Comparing f(x) = 4x2 - 8kx - 9 with ax2+bx+c we get

a=4; b=-8k and c=-9.

Since one root is the negative of the other, let us assume that the roots are p an -p.

Sum of the roots, a+(-a)=-b/a= - (-8k) / 4

0=2k

k=0

I hope this will help you..

Answer 2

Explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.