Question

If one of the zero of4x2-9-8kx is negative of the other find k

Answer 1

Answer:

Step-by-step explanation:

Let α and β be the zeros of the polynomial 4x²-8kx-9

It is given that α=-β

Then, α+β=0

-b/a=0

-(coefficient of x)/coefficient of x²=0

8k/4=0

2k=0

k=0

Answer 2

Let one of Zero of the polynomial be " T"

then the other zero will be negative of it that is -T

Now, equate the quadratic equation to zero as it satisfies it.

4x² - 9 - 8kx = 0

Apply,

▶ sum of zeroes = -b/a

(coefficient of variable "x" ---— ax² +bx+c)

T +(-T) = -(-8k)/4

0 = 2k

2k = 0

K = 0

Answer Value of K= 0

Thanks!