Question

If one of the zero of4x2-9-8kx is negative of the other find k​

Answer 1

Let one of Zero of the polynomial be " T"

then the other zero will be negative of it that is -T

so,

equate the quadratic equation to zero as it satisfies it.

By question

4x² - 9 - 8kx = 0

sum of zeroes = -b/a

T +(-T) = -(-8k)/4

0 = 2k

2k = 0

K = 0

Answer 2

Comparing f(x) = 4x2 - 8kx - 9 with ax2+bx+c we get

a=4; b=-8k and c=-9.

Since one root is the negative of the other, let us assume that the roots are p an -p.

Sum of the roots, a+(-a)=-b/a= - (-8k) / 4

0=2k

k=0