Question

if one of the zeroes of a quadratic polynomial (k-1) x²+ Kx+1 is -3 then the various of k is​

Answer 1

Step-by-step explanation:

∴ d = 0 d = b2 – 4ac d = (4k)2 – 4

(k2 – k + 2)

(1) d = 16k2 – 4

k2 + 4k – 8

Put d = 0 0 = 16

k2 – 4k2 + 4k – 8 12

k2 + 4k2 + 4k – 8 = 0

(divide by 4)

3k2 + k – 2 = 0 3k2 + 3k – 2k – 2 = 0 3k

(k + 1) – 2k (k + 1) = 0

(3k–2k)(k+1) = 0

(3k–2k)=0 or

(k+1) = 0

k = 0

k = –1