If one of the zeroes of quadratic polynomial 14x^2-42k^2x-9 is negative of other,find k
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Answer:
a=14 b=42k^2 c=9
Alpha=-Beta -Equation 1
Alpha+Beta = -b/a
From 1
-Beta+Beta=-(42k^2)/14
0=3k^2
0=k^2
k=0
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