Question

if one of the Zeroes of quadratic polynomial (k-1) x²+kx+1 is "-3" then the value of 'k' is...​

Answer 1

Answer:

Given −3 is the zero of the polynomial (k−1)x

2

+kx+1

So −3 must satisfy the equation (k−1)x

2

+kx+1=0

⟹(k−1)(−3)

2

+k(−3)+1=0

⟹9(k−1)−3k+1=0

⟹9k−9−3k+1=0

⟹6k=8

⟹k=

3

4

Answer 2

Step-by-step explanation:

Given:

$(k - 1) {x}^{2} + kx + 1$

If one zero of quadratic polynomial is -3.

To find: Value of k.

Solution:

Tip: Put the value of zero in polynomial.

If we put zero in the polynomial,the polynomial must become zero.

$(k - 1)( { - 3)}^{2} + k( - 3) + 1 = 0 \\ \\ 9(k - 1) - 3k + 1 = 0 \\ \\ 9k - 9 - 3k + 1 = 0 \\\\ 6k - 8 = 0 \\ \\ 6k = 8 \\ \\ k = \frac{8}{6} \\ \\ \bold{\red{k = \frac{4}{3}}}$

Final answer:

Value of k is 4/3.

If -3 is a zero of (k-1) x²+kx+1.

Hope it helps you.

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