if one of the zeroes of quadratic polynomial (k-1)xsquare + kx + 1 is -3 then find k
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Here is the solution
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If it helps you then plz mark it as brainliest answer
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Step-by-step explanation:
GIVEN:-)
→ One zeros of quadratic polynomial = -3.
→ Quadratic polynomial = ( k - 1 )x² + kx + 1.
Solution:-
→ P(x) = ( k -1 )x² + kx + 1 = 0.
→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.
=> ( k - 1 ) × 9 -3k + 1 = 0.
=> 9k - 9 -3k + 1 = 0.
=> 6k - 8 = 0.
=> 6k = 8. ...
Hence, the value of ‘k’ is founded .
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