Question

If one of the zeroes of the cubic polinomial x³+ ax² + bx +c is -1 then the product of other two zeroes is ?

Answer 1

an algebraic equation of the third degree. The general form of a cubic equation is

ax3 + bx2 + cx + d = 0
where a ≠ 0. By replacing x in this equation by a new unknown y related to x by x = y − b/3a, a cubic equation can be reduced to the simpler (canonical) form
y3 + py + q = 0
where
p = b2/3a2 = c/a
q = 2b2/27a3 − bc/3a2 + da
The solution of this equation can be found using Cardan’s formula

If the coefficients of a cubic equation are real, then the nature of its roots depends on the sign of the radicand q2/4 + p/27 in Cardan’s formula. If q2/4 + p3/4 + p3/27 > 0, then the cubic equation has three different roots, one real and two complex conjugates. If q2/4 + p327 = 0, then all three roots are real, two of them being equal. If q2/4 + p3/27 > 0, then the three roots are real and different. The expression q2/4 + p3/27 differs by a constant factor from the discriminant of a cubic equation D = −4p3 − 27q2.

Answer 2

Step-by-step explanation:

$\bf\huge{Question:-}$

If one of the zeroes of the cubic polinomial x³+ ax² + bx +c is -1 then the product of other two zeroes is ?

$\bf\huge{answer:-}$

refer the attachment