if one of the zeroes of the cubic polynomial ax^3+bx+cx+d is zero,then the product of other two zero is?
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The above polynomial can be rewritten as ax^3+(b+c)x+d
let the zeroes be α,β,Φ
if α=0, then
αβ+βΦ+αΦ=0+βΦ+0=(b+c)/a
let the zeroes be α,β,Φ
if α=0, then
αβ+βΦ+αΦ=0+βΦ+0=(b+c)/a
nishant45:
wrong
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heya it's Aastha......
b) Let p(x) =ax3 + bx2 + cx + d
Given that, one of the zeroes of the cubic polynomial p(x) is zero.
Let α, β and γ are the zeroes of cubic polynomial p(x), where a = 0.
We know that,
then,
sum of product of zeroes = c/a
alpha × beta + beta× gamma + gmma × alpha = c/a
0 × beta + beta × gamma + gamma×0 =c/a
beta / gamma = c/a ..
Hence ,
The other two zeroes are c /a .
Hope it help u ✌️✌️
b) Let p(x) =ax3 + bx2 + cx + d
Given that, one of the zeroes of the cubic polynomial p(x) is zero.
Let α, β and γ are the zeroes of cubic polynomial p(x), where a = 0.
We know that,
then,
sum of product of zeroes = c/a
alpha × beta + beta× gamma + gmma × alpha = c/a
0 × beta + beta × gamma + gamma×0 =c/a
beta / gamma = c/a ..
Hence ,
The other two zeroes are c /a .
Hope it help u ✌️✌️
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