Question

If one of the zeroes of the cubic polynomial x + ax? + bx + c is -1, then
the product of the other two zeroes is
ab-a +1
b) b-a-1 (c) a-b+1 (d) a-b-1​

Answer 1

Answer:

option a : b - a + 1

Step-by-step explanation:

x3 +ax2 + bx + c

one root is -1 hence

(-1)^3 + a(-1)^2 +b(-1)+c = 0

-1 + a - b + c = 0

c = b - a + 1

Now we know that product of roots of a cubic polynomial ax3+bx2+xx+d is -d/a

in this case

d = c

a= 1

so product of roots

= (-1)*(product of other two rrots) = -c/1

product of two roots = c = b-a+1