if one of the zeroes of the cubic polynomial x^+ax^+bx+c is -1 , then the product of the other two zeroes is :
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Answer:
c/a
Step-by-step explanation:
f×(0)=a×3-bx²+c×+d
⇒d=0
⇒Now, f×(x) is x(aײ-b×+c)
So, product will be=c/a
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