Question

If one of the zeroes of the cubic polynomial x3 + ax² + bx + c is -1, then the product of the other two zeroes is

Answer 1

Answer:

C

Step-by-step explanation:

x^3+ax^2+bx+c

the product of roots= -c

i.e pqr = -c

pq(-1)= -c

pq= c

the product of other two roots is c

Answer 2

Step-by-step explanation:

$let \: the \: other \: two \: is \: \alpha \: and \: \beta \\ then \: \\ product \: of \: roots = \frac{ - c}{a} \\ \alpha \beta \times ( - 1) = \frac{ - c}{a=1} \\ \alpha \beta = \frac{c}{a=1} \\ this \: is \: the \: required \: result \: ... \\ \\ hope \: it \: helps \: you...$