Question

If one of the zeroes of the cubic polynomial x3 + ax² + bx + c is -1, then the product of the
other two zeroes is​

Answer 1

Answer:

given below

Step-by-step explanation:

f(x) = x³+ax²+bx+c/0

f(x) = 2

f(2) = 2³+a(2)²+ b(2)+c=0

8+2(4)+ 2b+c=0

8+8+2b+c=0

16+2b+c=0

2b+c=-16

b+c=-16/2

b+c=8

so, b=8 and c=8