If one of the zeroes of the cubic polynomial x³+ ax²+ bx + c is -1, then the product of the other two zeroes is:
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A. b - a + 1
let α, β & γ be the zeroes of the polynomial
p(x) = x3 + ax2 + bx + c and
α = - 1 (given)
Zeroes of a polynomial is all the values of x at which the polynomial is equal to zero. i.e.
p (α) = p(- 1) = 0
= (- 1)3 + (- 1)2a + (- 1)b + c = 0
= - 1 + a - b + c = 0 = c = 1 - a + b Product of zeroes = - (constant term) ÷ coefficient of x3 i.e. Product of zeroes = - c αβγ = - c = βγ = c = βγ = 1 - a + b
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